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01-04-2019
Mathematics

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P(A)=0.22 and P(B)=0.46
Find P(A OR B)

PA022 and PB046 Find PA OR B class=

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01-04-2019

In general, the probability of a disjunction is

[tex]P(A \lor B) = P(A)+P(B)-P(A\cap B)[/tex]

In this case, A and B are mutually exclusive, so [tex]P(A\cap B)=0[/tex]

This simplifies the formula to

[tex]P(A \lor B) = P(A)+P(B) = 0.22+0.46 = 0.68[/tex]

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