alextamayo16 alextamayo16
  • 04-06-2019
  • Mathematics
contestada

What is the solution set of the following equation? 4/5 x2 = 2x - 4/5

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kudzordzifrancis
kudzordzifrancis kudzordzifrancis
  • 04-06-2019

Answer:

[tex]x=\frac{1}{2}[/tex] or [tex]x=2[/tex]

Step-by-step explanation:

The given quadratic equation is:

[tex]\frac{4}{5}x^2=2x-\frac{4}{5}[/tex]

We multiply through by 5 to get:

[tex]4x^2=10x-4[/tex]

Rewrite in standard quadratic form;

[tex]4x^2-10x+4=0[/tex]

Or

[tex]2x^2-5x+2=0[/tex]

Split the middle term to get:

[tex]2x^2-4x-x+2=0[/tex]

Factor to get:

[tex]2x(x-2)-1(x-2)=0[/tex]

Factor further to get:

[tex](2x-1)(x-2)=0[/tex]

Either [tex](2x-1)=0[/tex] or [tex](x-2)=0[/tex]

Either [tex]x=\frac{1}{2}[/tex] or [tex]x=2[/tex]

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