markvelazquez1
markvelazquez1 markvelazquez1
  • 02-07-2019
  • Mathematics
contestada

What is the standard form of the equation of a circle that has its center at (-2, -3) and passes through the point (-2, 0)?

Respuesta :

altavistard
altavistard altavistard
  • 06-07-2019

Answer:

(x - h)^2 + (y - k)^2 = 3^2

Step-by-step explanation:

The most general standard form here is

(x - h)^2 + (y - k)^2 = r^2.  Since we know the center is at (-2, -3), we rewrite this equation as

(x + 2)^2 + (y + 3)^2 = r^2.

Note that the center (-2, -3) and the point (-2, 0) lie on the same vertical line, and that the vertical distance from the center to this point is 3.  This is also the radius of the circle.  Thus, the equation of this circle is:

(x - h)^2 + (y - k)^2 = 3^2

Answer Link

Otras preguntas

What is the sign of the product of three integers with the same sign
The data showed that there was no significant difference in healing times between the two groups, so the researcher concluded that calcium intake has no effect
what is the cube answer to 24
What is the discount of 97.99 83.30
What is the next logical statement in the proof below? given: M is the midpoint of AB prove:2(AM) = AB a) AM+AM=AB b) AM=AB-MB c) AB=AM+MB d) M (A+B)=AB
The main trade route that connected China with Rome was called the _____. Satin Road Silk Road Han Road Roman Road
Is 11/20 and 17/40 and 1/12 either a repeating decimal or a terminating?
find the mean of 11,-7,-14,10,-5
The Velvet Revolution took place in _____. Romania Bulgaria Poland Czechoslovakia
Prudence means acting with ______. a. Self restraint b. Fairness c. Caution d. Honesty