Answer: [tex](x+6)^{2}+(y+5)^{2}=r^{2}[/tex]
Step-by-step explanation:
The formula for finding the equation of circle with center (a,b) is given as :
[tex](x-a)^{2}+(y-b)^{2}=r^{2}[/tex]
The end point of the diameter is given as :
(-10, -6) and (-2, -4) , this means that the coordinate of the center is the Mid -point of the end point .
The mid - point = ( -6 , - 5)
substituting into the formula , we have
[tex](x-(-6))^{2}+(y-(-5))^{2}[/tex][tex]= r^{2}[/tex]
[tex](x+6)^{2}+(y+5)^{2}=r^{2}[/tex]
This is the equation of the circle
