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1) A balloon is filled with helium to a volume of 13.6 Lat a pressure of
101 kPa. If the pressure decreases to 35.0 kPa what is the new volume
of the balloon (assuming temperature is constant)? (Boyle's Law)

Respuesta :

Neetoo

Answer:

Final volume = 835 L

Explanation:

Given data:

Initial volume = 13.6 L

Initial pressure = 101 Kpa

Final pressure = 35.0 KPa

Final volume = ?

Solution:

The given problem will be solved through the Boly's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

Pā‚Vā‚ = Pā‚‚Vā‚‚

Pā‚ = Initial pressure

Vā‚ = initial volume

Pā‚‚ = final pressure

Vā‚‚ = final volume Ā 

Now we will put the values in formula,

Pā‚Vā‚ = Pā‚‚Vā‚‚

101 KPa Ɨ 13.6 L = 35 KPa Ɨ Vā‚‚

Vā‚‚ = 1373.6 KPa. L/35 KPa

Vā‚‚ = 835 L

Answer:

39.2

Explanation:

using p1xv1=p2xv2

101x13.6= 1373.6

1373.6/35.0 =39.2457

round because of sigfig :)

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