hssanarsalan12
hssanarsalan12 hssanarsalan12
  • 01-07-2020
  • Mathematics
contestada

PLEAE ANS IT FAST PLESE

PLEAE ANS IT FAST PLESE class=

Respuesta :

rebeccarayshma
rebeccarayshma rebeccarayshma
  • 01-07-2020

Answer:

[tex] \frac{2}{ {x - 1}^{2} } - \frac{1}{x + 1} - \frac{1}{x + 1} = 0[/tex]

[tex] \frac{2}{(x + 1)(x - 1)} - \frac{1}{x + 1} - \frac{1}{x + 1} = 0[/tex]

[tex] \frac{2}{(x + 1)(x - 1)} - \frac{2}{x + 1} = 0[/tex]

[tex] \frac{2 - 2(x - 1)}{(x + 1)(x - 1)} = 0[/tex]

[tex] \frac{2 - 2x + 2}{(x + 1)(x - 1)} = 0[/tex]

[tex] \frac{4 - 2x}{(x + 1)(x - 1)} = 0[/tex]

[tex]4 - 2x = 0(x + 1)(x - 1)[/tex]

[tex]4 - 2x = 0[/tex]

[tex] - 2x = - 4[/tex]

[tex]x = \frac{ - 4}{ - 2} [/tex]

[tex]x = 2[/tex]

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