20100338110052 20100338110052

01-08-2020
Chemistry

contestada

6. The given mass of helium occupies
a volume of 250 cm3 at 10 OC and
0.2 atm. What will be its volume at 12
OC and 1.4 atm?
A
29 76 cm3

Respuesta :

pnwanosikeapps pnwanosikeapps

01-08-2020

Answer:

V2 = 35.967cm^3

Explanation:

Given data:

P1 = 0.2atm

P2 = 1.4atm

V1 = 250cm^3

V2 = ?

T1 = 10°C + 273 = 283K

T2 = 12°C + 273 = 285K

Apply combined law:

P1xV1/T1 = P2xV2/T2 ...eq1

Substituting values:

0.2 x 250/283 = 1.4 x V2/285

Solve for V2:

V2 = 14250/396.2

V2 = 35.967cm^3

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