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11-10-2016
Mathematics

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If p(x) = x^2 – 1 and q(x)=5(x-1), which expression is equivalent to (p – q)(x)? 5(x – 1) – x^2 – 1 (5x – 1) – (x^2 – 1) (x^2 – 1) – 5(x – 1) (x^2 – 1) – 5x – 1

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nobillionaireNobley nobillionaireNobley

13-10-2016

p(x) = x^2 - 1
q(x) = 5(x - 1)
(p - q)(x) = p(x) - q(x) = (x^2 - 1) - 5(x - 1)

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