imanigor20 imanigor20
  • 03-02-2021
  • Chemistry
contestada

A typical engagement ring has 0.77 cm^3 of gold. What mass is present?

Respuesta :

Neetoo
Neetoo Neetoo
  • 04-02-2021

Answer:

Mass = 14.876 g

Explanation:

Given data:

Volume of gold = 0.77 cm³

Mass of gold = ?

Solution:

Density of gold from literature is 19.32 g/cm³

Formula:

d = m/v

d = density

m = mass

v = volume

by putting values,

19.32 g/cm³ = m/ 0.77 cm³

m = 19.32 g/cm³ × 0.77 cm³

m = 14.876 g

Answer Link

Otras preguntas

Someone plz help me read the questions (giving brainliest!)
Pierre aime les légumes? Il ne ________ aime pas, mais moi je ________ aime. les l' la le Tu aimes le chocolat? Bien sûr, je ________ adore! te la les l
Maintaining a healthy body depends on:
A length of a rectangle is 16/9,. and its width is 3/4 of its length. Find the area of this rectangle
Explain what a rational exponent such as 5/2 means. Use this explanation to evaluate 9^5/2
state if polygons are similar
What is the unit of a force, and what is 1 unit equivalent to?
Why are graphic designers so important in Today's society?
Nicole runs 3 miles in 28 minutes. At the same rate, how many miles would she run in 42 minutes?
Use complete sentences to describe why postulates are helpful.​