Violet4174 Violet4174
  • 01-04-2021
  • Mathematics
contestada


Factor completely
486+108x+6x^2

Thank you!

Respuesta :

hailydenney2
hailydenney2 hailydenney2
  • 01-04-2021

Answer:

6(x + 9) (x + 9)

or

[tex]6 (x+9)^{2}[/tex]

Step-by-step explanation:

[tex]468 + 108x + 6x^{2} \\6x^{2} +108x + 468[/tex]

Greatest common factor of 6, 108, and 486:

6 x 1 = 6

6 x 18 = 108

6 x 81 = 486

GCF: 6

so:

[tex]6(x^{2} +18x +81)[/tex]

[tex]x^{2} +18x + 81[/tex]

factors to:

(x + 9) (x + 9)

because:

9 x 9 = 81

9 + 9 = 18

So:

It factors completely too:

6(x + 9) (x + 9)

or

[tex]6 (x+9)^{2}[/tex]

Answer Link

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