carolina3620 carolina3620
  • 04-04-2021
  • Chemistry
contestada

how many grams are there in 1.77 x 10^22 atoms of beryllium

Respuesta :

drpelezo
drpelezo drpelezo
  • 04-04-2021

Answer:

0.265 grams Be (3 sig. figs. per coefficient of given 1.77 x 10²² atoms Be)

Explanation:

Calculation Sequence: #atoms => #moles by dividing by Avogadro's Number (6.02 x10²³) => #grams (multiply #moles by Be formula weight - 9.012g/mol

Given 1.77 x 10²² atoms Be = 1.77 x 10²² atoms Be x 1 mole Be/6.02 x 10²³ atoms Be/mole Be x 9.012 g Be/mole Be = 0.26497 (calculator answer)

= 0.265 grams Be (3 sig. figs. per coefficient of given 1.77 x 10²² atoms Be)

Answer Link

Otras preguntas

What is A direct and indirect quote i need to know so i can revise my essay please explain
1. List and explain the difference between the minimum voltage and maximum voltage achieve in a nerve impulse
Please help quickly! (:
You are writing an essay on the life of Napoleon Bonaparte and are using information from this source. Which sentence is an example of paraphrase and not plagia
How is a vocation both a call from god and a response to god?
The children wishes they could get a new horse. Is this a complete and proper sentence?
If a ball is given an acceleration of 3.0 meters/second^2 while being pushed with a force of 0.75 newtons, what is the mass of the ball?
How are desert plants adapted to their climate?
0.005098 megaliters to liters. Show your work.
PLEASE HELP ASAP I WILL MARK BRILLIANT WHOEVER ANSWERS THANKS (: