michellexjada michellexjada
  • 02-06-2022
  • Mathematics
contestada

Solve 4|3x-1| + 3 > 11.

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199932
199932 199932
  • 03-06-2022

4|3x-1| + 3 > 11

4|3x-1| > 11-3

4|3x-1| > 8

|3x-1| > 2

3x-1>2 or 3x-1<-2

3x>2+1 3x<-2+1

3x>3 3x<-1

x>1 x<-1÷3

Solution: ]-♾️ , -1÷3 [ U ] 1,+♾️ [

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